CHEM 3523 - Supplementary Problems

Vibrational Spectroscopy

Question 1

a. SiCl4

3N = 15
3N-6 = 9

TdE8C33C26S4d
Γtotal150-1-13

Reduces to: A1 + E + T1 + 3T2

 A1ET13T2
Translations   (Tx,Ty,Tz)
Rotations  (Rx,Ry,Rz) 
VibrationsA1E 2T2
IR Active   Yes
Raman ActiveYesYes Yes

IR = 2T2
Raman = A1 + E + 2T2


b. trans-SF2Cl4

3N = 21
3N-6 = 15

D4hE2C4C22C2'2C2"i2S4σhvd
Γtotal213-3-3-1-3-1553

Reduces to: 2A1g + A2g + B1g + B2g + 2Eg + 3A2u + B2u + 4Eu

 2A1gA2gB1gB2g2Eg3A2uB2u4Eu
Translations     Tz (Tx,Ty)
Rotations Rz  (Rx,Ry)   
Vibrations2A1g B1gB2gEg2A2uB2u3Eu
IR Active     Yes Yes
Raman ActiveYes YesYesYes   

IR = 2A2u + 3Eu
Raman = 2A1g + B1g + B2g + Eg


c. SbCl5

3N = 18
3N-6 = 12

D3hE2C33C2σh2S3v
Γtotal180-24-24

Reduces to: 2A1' + A2' + 4E' + 3A2" + 2E"

 2A1'A2'4E'3A2"2E"
Translations  (Tx,Ty)Tz 
Rotations Rz  (Rx,Ry)
Vibrations2A1' 3E'2A2"E"
IR Active  YesYes 
Raman ActiveYes Yes Yes

IR = 3E' + 2A2"
Raman = 2A1' + 3E' + E"


d. CH2Cl2

3N = 15
3N-6 = 9

C2vEC2σvσv'
Γtotal15-133

Reduces to: 5A1 + 2A2 + 4B1 + 4B2

 5A12A24B14B2
TranslationsTz TxTy
Rotations RzRyRx
Vibrations4A1A22B12B2
IR ActiveYes YesYes
Raman ActiveYesYesYesYes

IR = 4A1 + 2B1 + 2B2
Raman = 4A1 + A2 + 2B1 + 2B2